In a forum thread about Torah proofs, the following claim popped up (edited for clarity):

every lashon Hakodesh noun word in Torah, if you add it [the Gematria values of all letters] up minus the misper kuton [the digit sum] will equal 9 which is gematria of emes to show that the Torah is emes.

So the claim is: Add the letters, subtract the digit sum and the result is evenly divisible by nine.

A few Hebrew examples:

שָּׁמַ֖יִם (heaven) = 300 + 40 + 10 + 40 = 390 , digit sum 12 -> 390 – 12 = 378, 378 by 3 is 126

אָֽרֶץ (earth) = 1 + 200 + 90 = 291, digit sum 12 -> 291 – 12 = 279, 279 by 3 is 93

ר֣וּחַ (wind, breath) = = 200 + 6 + 8 = 214, digit sum 7 -> 214 – 7 = 207, 207 by 3 is 69

Amazing? Not so much.

Let’s take a three-digit number and let the digits of it be represented by the variables ABC. A is the first digit, B the second, C the third. If A is 1, B is 2, and B is 5, we have the number 125. A in the number represents the hundreds, B the tens and C the ones. Mathematically speaking, a number is represented as:

A*100 + B*10 + C

The digit sum of a number is simply the sum of the components, for our three-digit number, that would be A+B+C. In the example 125, we have 1 + 2 + 5 = 8. So let’s subtract the digit sum from the original number:

A*100 + B*10 + C – (A + B + C)

Using some stuff you learned at school for grouping the variables, we can simplify this to give:

A*100 + B*10 + C – (A + B + C)

= 100*A + 10*B + C – A – B – C

= 100*A – 1*A + 10*B – 1*B + C – C

= (100 – 1) * A + (10 – 1) * B + C – C

= 99*A + 9*B

= 9 * (11*A + 1*B)

This result is a number that can be represented as 9*something. And if something can be represented as 9*something, it is divisible by 9 (in Math-talk: 9 is a divisor of the number).

So EVERY number minus its digits sum is divisible by nine. The numerical values of words from the Torah are not special in any way, the values for ALL words in the worlds, no matter which language are divisible by nine.